How do you count the vowels in a string?

Answer 1

#include #include void main() { char string[50]; int vowel=0,consonant=0; cout<<"Enter the string"; cin.getline(string,50); for(int i=0;string[i]!='\0';i++) { switch (string[i]) { case 'a': case 'A': case 'e': case 'E': case 'i': case 'I': case 'o': case 'O': case 'u': case 'U':vowel++; continue; } if (string[i]!=' ') consonant++; } cout<<"No of vowels="<<<"\nNo of consonants="<

Answer 2

A simple way to do this, whatever the language used, is to step through the characters in the string one by one and compare them with a previously established set of vowels, adding one to a count value every time a character matches one of the vowels. The count value at the end will be the number of vowels.

Remember to define the set of vowels and the count value and to check for an empty string and for the end of the string.

Here are some examples of programs that count the number of vowels in a string in different programming languages. C++ Example 1void main() {char *str; char a[]="aeiouAEIOU"; int i,j,count=0; clrscr(); printf("\nEnter the string\n"); gets(str); for(i=0;str[i]!='\0';i++) { for(j=0;a[j]!='\0';j++) if(a[j] == str[i] { count++; break;

}

printf("\nNo. of vowels = %d",count); getch();

}

} C++ Example 2#include

#include

int main (void) {char s[100];

int i,c=0;

clrscr();

printf("\n Enter a string");

scanf("%s",s); for(i=0;s[i]!='\0';i++)

{

if (s[i]=='a's[i]=='A's[i]=='e's[i]=='E's[i]=='i's[i]=='I's[i]=='o's[i]=='O's[i]=='u's[i]=='U') { c++;

}

}

printf("\nThe no. of vowels in the given string is=%d",c);

getch();

return 0;

}

} Javascript Exampleb = prompt("Enter the String","");

c=0;

for (i=0;i<b.length;i++) {if ("aeiou".indexOf(b.substr(i,1).toLowerCase())!=-1){ c++;

}

}

alert("No. of Vowels: "+c); PHP Example$vowels = array('a','e','i','o','u');

$string = 'An example string';

$length = strlen($string);

$count = 0;

for ($i = 0; $i !== $length; $i++;) {if (array_search($length[$i], $vowels)) { $count++;

}

}

echo 'There are (' . $count . ') vowels in the string (' . $string . ').';

Another way to do this would be through the use of RegExes/Pattern matching

Javascript Example:

str="A string for use of testing";

count= str.match(/[aeiou]/gi).length;

console.log("There are "+count+" vowels");

Java Example:

import java.util.regex.*;

public static void main(String[] args){

String str= "A string for use of testing";

Matcher m= Pattern.compile("(?i)[aeiou]").matcher(str);

int count= 0;

while (m.find()){

count+= m.end()-m.start();

}

System.out.println("There are "+count+" vowels");

}

Answer 3

#include<stdio.h>

#include<conio.h>

int main (void)

{

char s[100];

int i,c=0;

clrscr();

printf("\n Enter a string");

scanf("%s",s);

for(i=0;s[i]!='\0';i++)

{

if(s[i]=='a's[i]=='A's[i]=='e's[i]=='E's[i]=='i's[i]=='I's[i]=='o's[i]=='O's[i]=='u's[i]=='U')

c++;

}

printf("\n the nos. of vowels in the given string is=%d",c);

getch();

return 0;

}

Answer 4

//testing code

//note that a space character should be neither a vowel, nor a consonant

string s = "This is a test";

Console.WriteLine("Source string: {0}", s);

Console.WriteLine("# of Vowels: {0}",

GetCount(s, "aeiou"));

Console.WriteLine("# of Consonants: {0}",

GetCount(s, "bcdfghjklmnpqrstvwxyz"));

// helpers

// get number of characters in source that are in charactersToMatch

public int GetCount(string source, string charactersToMatch)

{

char[] target = charactersToMatch.ToCharArray();

int count = 0;

foreach (char c in source.ToLower()) {

if (IsMatch(c, target)) count++;

}

return count;

}

//returns true if c is one of patterns, false otherwise

public bool IsMatch(char c, char[] patterns)

{

foreach (char p in patterns) {

if (c == p) return true;

}

return false;

}

Answer 5

#include<iostream.h>

#include<conio.h>

main()

{

char str[10];

int v=0;

cout<<"Please enter a string: ";

cin>>str;

for(int i=0;str[i]!='\0';i++)

{

if(str[i]=='a'str[i]=='A'str[i]=='e'str[i]=='E'str[i]=='i'str[i]=='I'str[i]=='o'str[i]=='O'str[i]=='u'str[i]=='U')

v++;

}

cout<<" Number of Vowels are there.= "<<v;

getch();

}

Answer 6

#include

int str_vowels(char* s)

{

int numbers = 0;

int n = 0;

while(s[n]!='\0')

{

if(s[n]=='a's[n]=='e's[n]=='i's[n]=='o's[n]=='u')

{

numbers++;

}

n++;

}

return numbers;

}

int main()

{

char s[1024];

printf("Enter a string:");

scanf("%s", s);

printf("The numbers of vowels present in the string is %d\n", str_vowels(s));

return 0;

}

Answer 7

For PHP:

<?php

$string="umbrella";

echo "There are ".preg_match_all('/[aeiou]/',$string,$matches)." vowels in string "."<strong>".$string."</strong>";

?>

Answer 8

To find vowels present in string, you must first scan the string for values. Scan each letter on string (as characters) and analyze if they are vowels or not. You can use for loop (since loops are best used with arrays) and conditional statements to scan and analyze each letter. If and Else statements can be handy. But you can also use switch. Also, you will need to use <string.h> in extracting and analyzing words.

char strword[7] = "create"

length = strlen(strword);

for (ctr = 0; ctr < length; ctr++) {

if (strword[ctr] 'u') {

printf ("%c <-- This letter is a vowel\n", strword[ctr]);

}

}

Answer 9

In most cases you use C++, but for your general question, you use pseudocode.

Answer 10

Yes, you can, but you have to put codes of all vowels in your program.