Molecular:
Bacl2(aq)+K2SO4(aq)-->BaSO4(s)+2KCl(aq)
Total Ionic:
Ba+2(aq) + 2Cl-(aq) + 2K+(aq) + SO4-2(aq)-->BaSO4(s) + 2K+(aq) + 2Cl-(aq)
Net Ionic:
Ba+2(aq) + SO4-2(aq)-->BaSO4(s)
The ionic equation would have the ionic charges of each compound/element/or whatever. Ba^+2 CL^- for the first.. etc. You do the 'criss-cross' method to determine the ionic charges, and write that into the equation.
This is a double-replacement precipitation type of reaction.
Molecular:
Bacl2(aq)+K2SO4(aq)-->BaSO4(s)+2KCl(aq)
Total Ionic:
Ba+2(aq) + 2Cl-(aq) + 2K+(aq) + SO4-2(aq)-->BaSO4(s) + 2K+(aq) + 2Cl-(aq)
Net Ionic:
Ba+2(aq) + SO4-2(aq)-->BaSO4(s)
The ionic equation would have the ionic charges of each compound/element/or whatever. Ba^+2 CL^- for the first.. etc. You do the 'criss-cross' method to determine the ionic charges, and write that into the equation.
This is a double-replacement precipitation type of reaction.
First you develop the molecular formula:
BaCl2 (aq) + Na2S (aq) ---> BaS (aq) + NaCl (aq)
As you can see, the resulting products are both aqueous, which means there isn't a reaction. So you can't have a net formula.
I believe the answer would be something like
Molecular Equation:
BaCl2(aq) + H2SO4(aq) = 2HCl(aq) + BaSO4(s)
Ionic Equation:
Ba2+(aq) + Cl21-(aq) + H21+(aq) + SO42-(aq) = 2H1+(aq) + Cl1-(aq) + BaSO4(s)
Net Ionic Equation:
Ba2+(aq) + SO42-(aq) = BaSO4(s)
Barium chloride+ Sodium Carbonate yields Barium Carbonate + Sodium chloride BaCl2 (aq) + Na2CO3 (aq) --> BaCO3 (aq) + 2NaCl (aq) Net Ionic: Ba+ + CO3- --> BaCO3
This is a simple double replacement reaction:
K2S + BaCl2 = 2KCl + BaS
Net ionic equation for Na2SO4 + BaCl2 is as follows:
Ba^2+(aq) + SO4^2-(aq) ==> BaSO4(s).
Na^+ and Cl^- are spectator ions.
Ba^2+(aq)+SO4^2-(aq)-->BaSO4(s)
There is no reaction between those
Baco3
Na2O + H2O
H2so4+2koh=k2so4+2h2o
The formula for magnesium sulphate is MgSO4.You have not specified any reaction, so there is no way to write the equation for it!See the Related Questions to the left for how to write a balanced chemical reaction.
Go ahead and write the balanced equation: H2SO4 + 2NaOH --> Na2SO4 +2H2O If you have 1 mole of the reactant H2SO4, it will yield 2 moles of the product water. You can tell by the coefficients.
This reaction equation is usually written H2SO4 (aq) + Ca(OH)2 (aq) -> H2O + CaSO4 (aq) [or possibly (s), depending on the concentrations].
Na2O + H2O
The formula for magnesium sulphate is MgSO4.You have not specified any reaction, so there is no way to write the equation for it!See the Related Questions to the left for how to write a balanced chemical reaction.
H2so4+2koh=k2so4+2h2o
Go ahead and write the balanced equation: H2SO4 + 2NaOH --> Na2SO4 +2H2O If you have 1 mole of the reactant H2SO4, it will yield 2 moles of the product water. You can tell by the coefficients.
We see the chemical reaction but we write the chemical equation.
This reaction equation is usually written H2SO4 (aq) + Ca(OH)2 (aq) -> H2O + CaSO4 (aq) [or possibly (s), depending on the concentrations].
The balanced chemical equation for the reaction is BaCl2(aq) + 2 NaF(aq) → BaF2(s) + 2 NaCl(aq)
The equation for this reaction is CuO (s) + H2SO4 (aq) -> CuSO4 (aq) + H2O (l).
Phosphine is not very soluble in water compared to nonpolar substances. If you were to write a balanced equation for the reaction of PH3 with water, it would be an equilibrium reaction.
2KBr + 2H2O----->2KOH + Br2 + H2(g) this is the reaction in electrolysis of KBr in aqueous solution
An example is:2 KOH + H2SO4 = K2SO4 + 2 H2O
Of course, not !